a certain mass of a gas occupies to litres at 27 degree Celsius and hundred Pascal find the temperature when volume and pressure become half of the initial values
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75 kelvin by applying pv=nrt
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V1= 2 litres .
V2=1/2×2=1.
P1=100 Pascal.
P2=1/2×100 pascal.
T1=27°C=273+27=300 K
T2=?.
Applying the formula of gas law,
V1 P1/T1=V2P2/T2.
2×100/300=1×50/T2
T2=50×1×300/2×100
T2=75 K
T2=(75-273)°C
T2=-198°C
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