Question

A certain mass of air, initially at a pressure of 480kPa and temperature 1900C  is expanded adiabatically to a pressure of 94kPa.It is then heated at constant volume until it attains its initial temperature when the pressure is found to be 150 kPa. State the type of compression necessary to bring the system back to its original pressure and volume. Find (i) the index of adiabatic expansion and (ii) the work done per kg of air. Plot P-v/T-v diagram using excel and label and shade work done by the steam on plot. State the final state of the steam.

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Answer 1

Explanation:

For an isothermal process:

For an isothermal process:PV=constant

For an isothermal process:PV=constantPdV=−dPV

For an isothermal process:PV=constantPdV=−dPVdV

For an isothermal process:PV=constantPdV=−dPVdVdP

For an isothermal process:PV=constantPdV=−dPVdVdP

For an isothermal process:PV=constantPdV=−dPVdVdP =

For an isothermal process:PV=constantPdV=−dPVdVdP = V

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constant

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdV

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ V

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1 and volume V

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1 and volume V 1

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1 and volume V 1

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1 and volume V 1 . It is compressed isothermally hence volume decreases and pressure increases with hyperbola.

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1 and volume V 1 . It is compressed isothermally hence volume decreases and pressure increases with hyperbola.Then it is expand adiabatically until its pressure returns to P

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1 and volume V 1 . It is compressed isothermally hence volume decreases and pressure increases with hyperbola.Then it is expand adiabatically until its pressure returns to P 1

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1 and volume V 1 . It is compressed isothermally hence volume decreases and pressure increases with hyperbola.Then it is expand adiabatically until its pressure returns to P 1

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1 and volume V 1 . It is compressed isothermally hence volume decreases and pressure increases with hyperbola.Then it is expand adiabatically until its pressure returns to P 1 the graph is little steeper hyperbola than isothermal graph,.

For an isothermal process:PV=constantPdV=−dPVdVdP = V−P for adiabatic process:PV γ =constantdVdP =−γ VP A certain mass of an ideal gas is at pressure P 1 and volume V 1 . It is compressed isothermally hence volume decreases and pressure increases with hyperbola.Then it is expand adiabatically until its pressure returns to P 1 the graph is little steeper hyperbola than isothermal graph,.The gas is then allowed to expand its original volume.represents a straight line with zero slope to pressure axis and at increasing volume. best represented by.

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