A certain mass of ammonia occupies 600ml at certain pressure when the pressure is changed to 480 atmospheric pressure it occupies a volume of 2.4 liters when temperatures is constant what was initial pressure?
Answers
Answered by
1
V1=600mL=0.6 L
P1=?
V2=2.4 L
P2=480 atm pressure
According to Boyle's law,
P1V1=P2V2
P1×0.6=2.4×480
P1=1152/0.6
P1=1920 atm pressure.
Similar questions