Question

A certain metal gives two oxides. In the 1st oxide
the percentage of oxygen is 22.5% and in the 2nd
oxide the percentage of oxygen is 36.8%
respectively. If the formula of the 1st oxide is MO
then formula of the 2nd oxide will be
(1) M,04
(2) M₂0
MO
(4) M.O.​

Answer 1

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12th

Chemistry

The p-Block Elements

Simple Oxides

Two oxides of a metal conta...

CHEMISTRY

Two oxides of a metal contain 27.6% and 30.0% of oxygen, respectively. If the formula of the first oxide be M3O4, find that of the second oxide.

A

MO3

B

M2O

C

M2O3

D

MO

MEDIUM

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ANSWER

Given that, formula of first oxide=M3O4

Let mass of the metal = x

% of metal in M3O4 =3x+643x×100

But  as given % age =(100−27.6)=72.4%

so, 3x+643x×100 = 72.4

or x=56.

In 2nd oxide,

Given, oxygen = 30%, So metal = 70%

So, the ratio is

M:O=5670:1630

⟹1.25:

Answer 2

Answer:

the correct answer is 1 options

Explanation:

in given question we have to increase the% of oxygen no option is increasing other than 1st

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