A certain metal when irradiated with light
(v = 3.2 x 10^16 Hz) emits photo electrons with
twice kinetic energy as did photo electrons
when the same metal is irradiated by light
(v = 2.0 * 10^16 Hz). Calculate v, of electron?
(1) 1.2 x 10^14 HZ
(2) 8 x 10^15 Hz
(3) 1.2 x 10^16 Hz (4) 4 x 10^12 Hz
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Answer:
(KE)
1
=hv
1
−hv
0
(KE)
2
=hv
2
−hv
0
As, (KE)
1
=2×(KE)
2
∴hv
1
−hv
0
=2(hv
2
−hv
0
)
or, hv
0
=2hv
2
−hv
1
or, v
0
=2v
2
−v
1
=2×(2×10
16
)−(3.2×10
16
)
=0.8×10
16
Hz=8×10
15
Hz
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