Question

A certain metal when irradiated with light
(v = 3.2 x 1016 Hz) emits photo electrons with
twice kinetic energy as did photo electrons
when the same metal is irradiated by light
(v = 2.0 * 1016 Hz). Calculate v not
, of electron?
(1) 1.2 x 1014 Hz
(2) 8 x 1015 Hz
(3) 1.2 x 1016 HZ
(4) 4 x 1012 Hz​

Answer 1

Explanation:

HEY MATE .....

${ \: k.e.}1 = 2{k.e.}2 \\ \\ hv \: 1 - hv \: 0 = 2{hv \: 2 \: - hv \: 0} \\ \\ hv \: 0 = 2hv2 - hv \: 1 \\ \\ v \: 0 = {2v2 - v1} \\ \\ = 2 \times 2 \times {10}^{16} - 3.2 \times {10}^{16} \\ \\ = 8 \times {10}^{15} hz$

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