Question

a certain mixture contains three chemicals A,B,C in the ratio 1/3:2/5:3/4 .what is the quantity of each chemical in into 2650 ml of the mixture.if the answer is 600 ml,720 ml , 1350 ml, then what are the steps.​

Answer 1

Answer:

Step-by-step explanation:

Given P,Q,R are in the ratio 1/3 : 2/5 : 3/4.

Total mixture = 2670 ml.

Let the common ratio be x.

⇒ (x/3) + (2x/5) + (3x/4) = 2670

⇒ (x * 20 + 24x + 25x)/60 = 2670

⇒ 89x/60 = 2670

⇒ 89x = 160200

⇒ x = 1800.

Now,

∴ Quantity of P = (1/3) * x

                        = 600

∴ Quantity of Q = (2/5) * x

                         = 720.

∴ Quantity of R = (3/4) * x

                        = 1350 ml.

Therefore, Quantity of P,Q,R are 600 ml, 720 ml, 1350 ml.

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Answer 2

Step-by-step explanation:

1350 is the correct answer....