A certain number between 10 and 100 is 8 times the sum of its digits
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Answer:
Step-by-step explanation:
let it be,
(x×10+y)=8(x+y)
10x-8x+y-8y
10x-8x+y+8y=0
2x-7y=0----(1)
10x+y-45=10y+x
10x-x+y-10y=45
9x-9y=45
x-y=5----(2)
2x-7y=0-----(1)
x-y=5-------(2)
2x-7y=0
2x-2y=10
+
---------
-5y=-10
(minus minus cut)
y=10
--. =2
2
x-2=5. (x=7
y=2)
x=7
x×10+y=7×10+2
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