A certain number between 10 and 100 is 8 times the sum of its agits, and if 45 is subtracted
from it, the digits will be reversed. Find the number.
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It could be 72 as it is 8 times the sum of its digits (7+2).
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Answer:
72
Step-by-step explanation:
Let the no. be 10x + y
10x+y=8(x+y) eq.1
10x+y=8x+8y
10x-8x=8y-y
2x=7y
x=7y/2
10x+y-45=10y+x eq.2
10x+y-10y-x=45
9x-9y=45
putting the value of x
9(7y/2)-9y=45
(63y-18y)/2=45
45y/2=45
45y=90
y=90/45
y=2
now, putting the value of y to find x
x=7y/2
x=7*2/2
x=7
So, the no. is 10x+y= 70+2
=72
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