Question

a certain number between 10 and 100 is 8 times the sum of its digits and if 45 is substracted from it, the digits will be reversed.find the number​

Answer 1

Answer:

Let the number between 10 and 100

= 10x + y

It is eight times the sum of its digits ⇒ 10x + y = 8(x + y) ⇒ 2x - 7y = 0 ....(1)

If 45 is subtracted from the number, the digits are reversed.

(10x + y) - 45 = (10y + x)

⇒ 9x - 9y = 45 ⇒ x - y = 5 .....(2)

By solving equations (1) and (2),

7y/2 - y = 5

5y/2 = 5

y = 2

So x = 7

we get x = 7 and y = 2.

Therefore, the original number is 72.

Answer 2

Answer:

it can be 4 because 4×8times=32 and 40-32 is 8 number or reversed number