Question

a certain number between 10 and 100 is 8 times the sum of its digits, and if 45 be subtracted from it the digits will be reversed. find the number.

Answer 1

let the number be xy 
value of number = 10x+y 
10x+y = 8(x+y) 
10x+y =8x+8y
2x-7y=0....................(1) 
10x+y-45 = 10y+x 
9x-9y=45 
x-y = 5.................(2) 
multiply by -2
-2x+2y=-10
add to (1) 
-5y=-10
y=2 
x-y =5 
x=7 
Number = 72
plss mark me as brainly

Answer 2

let it be,

(x×10+y)=8(x+y)

10x-8x+y-8y

10x-8x+y+8y=0

2x-7y=0----(1)

10x+y-45=10y+x

10x-x+y-10y=45

9x-9y=45

x-y=5----(2)

2x-7y=0-----(1)

x-y=5-------(2)

2x-7y=0

2x-2y=10

+

---------

-5y=-10

(minus minus cut)

y=10

--. =2

2

x-2=5. (x=7

y=2)

x=7

x×10+y=7×10+2

----------------------------------------------

✌️HOPE IT WILL HELP YOU✌️

PLZZ MARK IT AS BRAINLIST