a certain Number between 10 and 100 is 8 times the sum of its digit and if 45 be subtracted from it the digits Will be reversed. Find the Number
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let the number be 10x+y
given
10x+y=8(x+y)
2x-7y=0
and also
10x+y-45=10y+x
9x-9y=45
x-y=5
2x-2y=10
on solving them
-5y=-10
y=2
and thus x=7
and thus the number=10x+y=10*7+2=72
given
10x+y=8(x+y)
2x-7y=0
and also
10x+y-45=10y+x
9x-9y=45
x-y=5
2x-2y=10
on solving them
-5y=-10
y=2
and thus x=7
and thus the number=10x+y=10*7+2=72
Anonymous:
hey where did you give sum=7 in the question
I am sorry
It is correct
ok
mark it as brainliest
please bhai
OK tell me where u Got in answer 2x-2y=10
i.multiplied both sides by 2
understood
but why
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