Question

a certain number between 10 and 100 is 8 times the sum of its digits, and if 45 be subtracted from it the digits will be reversed. find the number

Answer 1

Answer:

jjahs

Step-by-step explanation:

ushjskagsgjsyeyeipqrwfwjeyf

Answer 2

Answer:

72

Step-by-step explanation:

Let the number have x in tens digit and y in ones digit

So the value of the number will be 10x + y

ATQ,

10x + y = 8(x + y)

10x + y = 8x + 8y

10x - 8x = 8y - y

2x = 7y

x = (7y)/2 [i]

Also,

10x + y - 45 = 10y + x

9x - 45 = 9y

9(7y)/2 - 45 = 9y [Plugging value of x from [i]]

63y/2 - 45 = 9y

63y/2 - 9y = 45

$\frac{63y - 18y}{2} =45\\45y = 90\\y = 2$

Putting value of y in [i]

x = ([7][2] / 2)

  = 7

The number is 10x + y

= (10)(7) + 2

= 72