A certain number cnsist of 2 digit .if 5 is added to the number and the result is divided by the units place digit the quotient is 6 .if 10 is substract from the number and the remai,der is divided by the sum of the digits the quotient is 3 what is the number
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et unit place is y
and tens place is x of two digit number
number 10x+y
and reverse number will be
10y+x
as per given conditions
10x+y=3(x+y)+7
and
10y+x +7(x+y)+3
solving these equations
we can get as
7x-2y=7 i
-6x+3y=3 ii
by solving both equations elimination method
we will get
X=3
and Y=7
two digit number whose tens place is 3 and unit place is 7
two digit number is 37
answer 37
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