Question

A certain number is divisible by 3 and also by 5. When the number is divided by 7, the remainder is 4. What is the smallest number that satisfies these conditions?

Answer 1

Answer:

The least common multiple of 2, 3, 4, 5, 6 is their LCM=60.

So, the answer is the least number such that it is a multiple of 7 and a multiple of 60 leaving remainder 1.

∴The required answer is 301.

Answer 2

Answer:

301

Step-by-step explanation:

The least common multiple of 2, 3, 4, 5, 6 is their LCM=60.

So, the answer is the least number such that it is a multiple of 7 and a multiple of 60 leaving remainder 1.

∴The required answer is 301.