Question

A certain number leaves a remainder 4 when divided by 6. The remainder when the number is divided by 9 is?

Answer 1

Answer:

Let number is 9 (Gives remainder 3 when divided by 6)

Now 926=816926=816

⇒⇒ Remainder = 3

Part of solved Number series questions and answers : >> Aptitude >> Number series

Answer 2

Answer:

The remainder will be 7 when the number is divided by 9.

Step-by-step explanation:

As per the question, a number is divided and the remainder is 4.

Let a number x which is divided by 6.

As we know, the remainder formula

Dividend = Quotient x Divisor + Remainder

According to question

x = 6q + 4

Squaring on the both the side

$\[\begin{gathered} {x^2} = {\left( {6q + 4} \right)^2} \hfill \\ {x^2} = 36{q^2} + 16 + 36q \hfill \\ {x^2} = 36{q^2} + 36q + 16 \hfill \\ {x^2} = 36{q^2} + 36q + 9 + 7 \hfill \\ {x^2} = 9\left( {4{q^2} + 4q + 1} \right) + 7 \hfill \\ \end{gathered} \]$

Since, when $x^2$ is divided by 9 leaves the remainder 7, when x is divided by 9 also leaves the remainder 7

Therefore, the remainder will be 7 when x is divided by 9.