A certain number leaves a remainder 4 when divided by 6. The remainder when the number is divided by 9 is
A)1 or 4
B)4 or 7
C)1 or 7
D)1 , 4 or 7
Answers
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Answer:
Sometimes the rigorous method works, sometimes trial and error works. In rare cases, the trial and error method is very instructive for future questions.
This again is a question that we need to solve by trial and error. Clearly, N is an odd number. So, the remainder when we divide N by 24 has to be odd.
If the remainder when we divide N by 24 = 1, then N2 also has a remainder of 1. we can also see that if the remainder when we divide N by 24 is -1, then N2 a remainder of 1.
When remainder when we divide N by 24 is ±3, then N2 has a remainder of 9.
When remainder when we divide N by 24 is ±5, then N2 has a remainder of 1.
When remainder when we divide N by 24 is ±7, then N2 has a remainder of 1.
When remainder when we divide N by 24 is ±9, then N2 has a remainder of 9.
When remainder when we divide N by 24 is ±11, then N2 has a remainder of 1.
So, the remainder when we divide N by 24 could be ±1, ±5, ±7 or ±11.
Or, the possible remainders when we divide N by 24 are 1, 5, 7, 11, 13, 17, 19, 23.
Or, the possible remainders when we divide N by 12 are 1, 5, 7, 11.
The question is "What are the possible remainders we can get if we divide N by 12?"
Hence the answer is "1, 5, 7, 11".
Choice A is the correct answer.