A certain number man can finish a piece of work in 50 days. If there are 7 more men, the work can be completed 10 days earlier. How many men were originally there?
Answers
Now, x men can finish work in 50 days.
So, x+7 men will do it in 50 *x /(x+7).
As per the question,
50x /(x+7) = 40
50x = 40x +280
10x = 280
x = 28.
So, No. of men originally there= 28.
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Given:
A certain number of men can finish the work in 50 days. If 7 more men are added to the team, the work can be completed 10 days earlier.
To Find:
The number of people who initially worked is?
Solution:
1. A certain number of men can finish the work in 50 days.
2. Let the initial number of men be assumed as x,
=> x men can finish the work in 50 days.
3. If there are 7 more men, the work can be completed 10 days earlier,
=> x + 7 men can finish the work 10 days earlier,
=> x + 7 men can finish the work in 40 days.
4. The initial number of men can be calculated as follows,
=> If it takes 50 days to complete a certain work in x days,
=> The time taken by x + 7 people to finish the same job is (50)*(x)/(x+7),
=> Time taken by x + 7 people to finish the job = 40 days,
=> (50x)/(x+7) = 40,
=> 50x = 40x + 280, ( solve for the value of x ),
=> 50x - 40x = 280,
=> 10x = 280,
=> x = 280/10,
=> x = 28.
5. Hence, Initial number of men = 28.
Therefore, the total number of men originally are 28.