Question

A certain number of men can complete a piece of work in 90 days if however there were 15 men less it would take 10 days more for the same work be completed how many men were there originally?​

Answer 1

Step-by-step explanation:

Let there be p men. They complete a work in 90 days. Hence the work requires the contribution of 90p men-days.

If the number of men was 8 less, the work would take 10 days more, or, (90+10)(p-8) men-days.

Equating the two we get

90p = (90+10)(p-8) =100(p -8) = 100p - 800, or

100p - 90p = 800, or

10p = 800, or

p = 80.

So there were 80 men in the originally.

Check: The work is done in 80*90 = 7200 men-days. With 72 men it would take 7200 men-days/72 men = 100 days. Correct.

Answer 2

Let X number of men were originally working.

Now coming to the question, 90X = 1 work

(X-8)*(90+10) = 1 work.

So, 90X = (X-8)100

100X -90X = 800

10X = 800

So , X = 80 men were originally working there.

HOPE IT WILL HELP YOU BRO