Question

A certain number of men can complete a piece of work in 90 days. If however there were 15 men less, it would take 10 days more for the same work to be completed. How many men were there originally?

Please answer this question asap but correctly and step-by-step. I’ll mark the best answer as the Brainliest. ​

Answer 1

Answer:

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Step-by-step explanation:

Let there be p men. They complete a work in 90 days. Hence the work requires the contribution of 90p men-days.

If the number of men was 8 less, the work would take 10 days more, or, (90+10)(p-8) men-days.

Equating the two we get

90p = (90+10)(p-8) =100(p -8) = 100p - 800, or

100p - 90p = 800, or

10p = 800, or

p = 80.

So there were 80 men in the originally.

Check: The work is done in 80*90 = 7200 men-days. With 72 men it would take 7200 men-days/72 men = 100 days. Correct.

HOPE IT HELPED U GUYS

Answer 2

Answer:

Statement of the given problem,

A certain number of men could complete a piece of work in 90 days. If there were 8 men less, it would take 10 days more. How many men were there originally?

Basic assumptions,

Let W denotes the whole given work.

Let N denotes the original number of men, who can complete the work W in 90 days.

Hence from above data we get following relation,

W/(N*90) = W/[(N - 8)*(90 + 10)] [= constant = amount of work done by 1 man in 1 day]

or (N - 8)*(90 + 10) = N*90 or 10*N = 800 or N = 80 [Ans]

Step-by-step explanation:

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