A certain number of men can finish a piece of work in 100 days. if there were 10 men less, it would take 10 days more for the work to be finished. how many men were there originally?
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let the original no. of men be x
then, x men needed 100days to complete.
when, x-10men were there, they needed 110days to finish the job.
use indirect proportion :- less men-more days.
x-10:x :: 100:110
x-10/x = 10/11
solve to get x as 110. that is, initially there were 110men.
then, x men needed 100days to complete.
when, x-10men were there, they needed 110days to finish the job.
use indirect proportion :- less men-more days.
x-10:x :: 100:110
x-10/x = 10/11
solve to get x as 110. that is, initially there were 110men.
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