A certain number of two digits is equal to 8 times the sum of the digits. The difference
between the tens and the ones digits is 5. Find the number.
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2 di=8ti the sum of the digits
sum of the digits=x
tens=y
one digits=y-5
(×+y)=number of the digts
(x+y)(y-5)
y^2+5x+yx-5y
=》y^2+x+xy=5y/5=1y
=y^2+x+x=1y/y=1
=y+2x=root1
y+x=1/2
y=1/2-x
(1/2-x-5)=4.5-x=0
x=4.5
x+y=4.5+0.5=5 Then the total number=5
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