A certain number subtraced from 18 and from 13 .the product of the two numbers obtained is 66.find the first numbers ? Plz show me easy calculations :-)
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let the number be x
according to question ,
(18-x) and (13-x)
(18-x)×(13-x) = 66
234-18x-13x+x² = 66
234-31x+x² = 66
234-66-31x+x² = 0
x²-31x+168 = 0
x²-24x-7x+168 = 0
x(x-24)-7(x-24) = 0
(x-24)(x-7) = 0
so , value of x can be = (x-24) = 0
=> 24
OR VALUE of x can be => (x-7) =0 => x= 7
hope this helps
any confusion then message me
according to question ,
(18-x) and (13-x)
(18-x)×(13-x) = 66
234-18x-13x+x² = 66
234-31x+x² = 66
234-66-31x+x² = 0
x²-31x+168 = 0
x²-24x-7x+168 = 0
x(x-24)-7(x-24) = 0
(x-24)(x-7) = 0
so , value of x can be = (x-24) = 0
=> 24
OR VALUE of x can be => (x-7) =0 => x= 7
hope this helps
any confusion then message me
Sweety2017:
thx so mch :-) for helping me
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