Physics, asked by Anonymous, 4 days ago

A certain object weight 300N at the earth's surface Determine the mass of the object in kg and it's weight in Newton when located on a planet with an acceleration of gravity equal to 4.0ft/s²​

Answers

Answered by Anonymous
10

GIVEN THAT :

  • Weight on Earth = 300 N
  • Value of g on the planet = 4 ft/s²

SO Convert it into m/s:

  • 4 ft/s² × (1 m / 3.3 ft) = 13.2 m/s²

Mass of the object:

 \bf \green{Weight = Mass × g }

  • Now replace the given value

 \bf300 = Mass  \times 9.8  [g = 9.8 m/s²]

 \bf{Mass = 300/9.8}

 \bf{Mass = 30.6 \:  kg}

 \bf \red{NOW}

  • Weight on the other Planet:

 \bf{Weight = Mass  \times  g} \\  \\  \bf{g \: means \: gravitational \: force \: present \: on \: that \:  planet}

 \bf{Weight = 30.6 \:  kg  \times 13.2  \: m/s²}

 \bf \boxed{Weight = 403.92 N}

Answered by shilpa85475
2

Weight of the object: \\ 300 N

Acceleration due to gravity on the earth surface( g): \\ 32 \frac{ft}{s^{2} } = 10\frac{ft}{s^{2} }

Weight= \\ m \times g

( where m= mass of the object and g= Acceleration due to gravity )

The mass of the object:

\\ =\frac{300}{10} \\= 30 kg

On another planet

The acceleration due to gravity(g') = \\ 4 \frac{ft}{s{2} } = 1.2\frac{ft}{s^{2} }

The mass of the object would remain the same.

The weight on the other planet = \\ m \times g'

\\= 30\times1.2\\=36 N

Hence, the weight on the other planet is 36 N

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