Chemistry, asked by Shushith6879, 11 months ago

A Certain Particle carries -2.5 *10^16 C of static charge.Calculate the number of electrons present.

Answers

Answered by sreeh123flyback
0

Answer:

1.5625×10^35 electrons

Explanation:

no of electrons if charge is given.

givencharge/charge of the particular substance

-2.5×10^16/1.6×10^-19c=1.5625×10^35electrons

charge of electron is 1.6×10^-19c

Answered by vamsivs58
0

Answer:

1.5625 * 10^35 electrons

Explanation:

charge is an integral multiple of charge of an electron.

let charge = q = -2.5 * 10^16

chargre of an electron = e =-1.6 * 10^-19

let n be the no.of electrons.

q = n*e;

-2.5 * 10^16 = n * (-1.6 * 10^-19)

n = 1.5625 * 10^35.

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