A Certain Particle carries -2.5 *10^16 C of static charge.Calculate the number of electrons present.
Answers
Answered by
0
Answer:
1.5625×10^35 electrons
Explanation:
no of electrons if charge is given.
givencharge/charge of the particular substance
-2.5×10^16/1.6×10^-19c=1.5625×10^35electrons
charge of electron is 1.6×10^-19c
Answered by
0
Answer:
1.5625 * 10^35 electrons
Explanation:
charge is an integral multiple of charge of an electron.
let charge = q = -2.5 * 10^16
chargre of an electron = e =-1.6 * 10^-19
let n be the no.of electrons.
q = n*e;
-2.5 * 10^16 = n * (-1.6 * 10^-19)
n = 1.5625 * 10^35.
Similar questions