Chemistry, asked by moksha5753, 8 months ago

A certain particle carries -6.4 x 10-19 coulombs of static charge. The number of electrons present in it is/are
(A) 4
(B) 6
(C) 2
(D) 1

Answers

Answered by PoojaBurra
0

Given:

Static charge of a particle = -6.4×10⁻¹⁹  C

To find :

The number of electrons present in the particle

Calculation:

The charge of a particle having ‘n’ electrons is given by the formula

       q = ne

By substituting the values given in the formula

  => q=ne

       -6.4×10⁻¹⁹= n×(-1.6×10⁻¹⁹)

        n = (-6.4×10⁻¹⁹) / (-1.6×10⁻¹⁹)

        n = 6.4 / 1.6

        n = 4

Final answer :

The number of electrons present in the particle is 4

Answered by dvenkat27
0

Given:

Static charge of a particle = -6.4×10⁻¹⁹  C

To find :

The number of electrons present in the particle

Calculation:

The charge of a particle having ‘n’ electrons is given by the formula

      q = ne

By substituting the values given in the formula

 => q=ne

      -6.4×10⁻¹⁹= n×(-1.6×10⁻¹⁹)

       n = (-6.4×10⁻¹⁹) / (-1.6×10⁻¹⁹)

       n = 6.4 / 1.6

       n = 4

Final answer :

The number of electrons present in the particle is 4

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