Chemistry, asked by deepanshubelwal5192, 10 months ago

A certain photochemical reaction is found to require 8.1 x 10-19 energy per water molecule.

Calculate the number of photons (per water molecule) of light with wavelength of 2.21x 10-6m

that is required to initiate the reaction​

Answers

Answered by abhi178
7

Therefore number of photons per water molecule is 9.

Given : A certain photochemical reaction is found to require 8.1 × 10^-19 J/water molecule.

To find : the number of photons (per water molecule) of light with wavelength of 2.21 × 10^-6 m that is required to initiate the reaction.

solution : we know from quantum theory,

Total energy = N × hc/λ

where N is the number of photons.

here , λ = 2.21 × 10^-6

so, hc/λ = (6.63 × 10^-34 × 3 × 10^8)/(2.21 × 10^-6)

= (6.63 × 3 × 10^-26)/(2.21 × 10^-6)

= 9 × 10^-20 J

total energy = 8.1 × 10^-19 J

so, 8.1 × 10^-19 = N × 9 × 10^-20

⇒81 × 10^-20 = N × 9 × 10^-20

⇒N = 9

Therefore number of photons per water molecule is 9.

Answered by choudhuryamita1978
1

Answer:

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