A certain piece of silver of given
mass is to be made like a wire.
Which of the following
combination of length (L) and the
area of cross-sectional (A) will
lead to the smallest resistance
A Land A
Feedback
B 2L and A/2
CL/2 and 2A
D Any of the above, because volume of
Answers
Answered by
3
Answer:
mark me brainlinest plzzzzz
Explanation:
The piece of a copper should be shaped with minimum wire for the resistance 'R'
Length of a wire is greater than its resistance 'L'
The cross-sectional area with less than resistance is 'A'
Therefore ,
resistivity of a material r with greater resistivity for its resistance
resistance = resistivity × length / area
'R=L/A'
From the question, the length and diameter should be ( L/ 2, 2D ) where resistance is minimum.
Similar questions