A certain product 'P' is made of two ingradients 'M' and 'N'
in the ratio 2:5. The price of 'M' is three times that of 'N'. The
total cost of the product is Rs. 52 per Kg. including labour charges
of Rs. 8 per Kg. Find the price of 'M' and 'N' per Kg.
Please explain well
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Answer:
Let the price of N per kg ₹ x. Then , the price of M per kg = ₹ 3 x
1 kg of P contains 2/7 kg of M and 5/7 kg of M
Price of 1 kg of p =(2/7)×3x+(5/7)x=(11/7)x
By the given condition, 11x/7
=52-8
=₹44
⇒x=44×(7/11)=₹28
Hence the price of N per kg = ₹ 28
the price of M is 3x=3*28=84
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