A certain quantity of a compound contains 0.9 gm Al and 0.8 gO .what is the empirical formula of the compound
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Al3O5
Explanation:
Al of 0.9g and O of 0.8g
Molar weight of aluminum = 27
Molar weight of oxygen = 16
Moles of Al = 0.9 / 27 = 9/ 270 = 1/ 30 = 0.03
Moles of O = 0.8 / 16 = 1/20 = 0.05
Ratio of the moles = 0.03 : 0.05 = 3:5
So the empirical formula would be Al3O5.
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