A certain quantity of a gas occupy a volume of 0.8 l
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1 litre of air contains 80% O2O2 by volume. So O2O2is 0.8 L.
At STP, 1 mole of O2O2 occupies 22.4 L. Hence , we can find how many moles occupy 0.8 L by n=0.822.4=0.0357n=0.822.4=0.0357 .
1 mole contains avagadro number(6.023×10236.023×1023) of particles. So, 0.0357 moles contains 0.0357×6.023×1023=2.15×10220.0357×6.023×1023=2.15×1022molecules
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At STP, 1 mole of O2O2 occupies 22.4 L. Hence , we can find how many moles occupy 0.8 L by n=0.822.4=0.0357n=0.822.4=0.0357 .
1 mole contains avagadro number(6.023×10236.023×1023) of particles. So, 0.0357 moles contains 0.0357×6.023×1023=2.15×10220.0357×6.023×1023=2.15×1022molecules
If you like my answer so please mark it as brainliest
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