Question

A certain quantity of electricity is passed through the aqueous solution of silver nitrate and copper sulphate solution in series if mass of silver deposit is 1.08g the mass of Cu deposited will be?

Answer 1

Answer:

Ag+ + e- ---> Ag

Cu2+ +2e- -----> Cu

From the above equations, we can see that to deposit one mole of silver, we need one mole of electrons, while to deposit one mole of copper, we need two moles of electrons.

The number of moles of copper deposited will half the number of moles of silver deposited.

Moles of silver deposited = 1.08/108 = 0.01

Moles of copper deposited = 0.01/2 = 0.005 moles

Mass of copper deposited = 0.005 x 63.5

= 0.3175 g