Question

A certain quantity of gas occupies a volume of 0.1 L when collected over water at 15°C and a pressure 0.95 atm .The same gas occupied a volume of 0.085 L at STP in dry conditions. Calculate the aqueous tension at 15°C.

Answer 1

Answer:

Solution

P

drygas

=P

observed

−aqueoustension

Aqueoustension=P

observed

−P

drygas

P

observed

=0.92

P

drygas

=?

According to combine gas law

T

1

P

1

V

1

=

T

2

P

2

V

2

[Experimental condition STP condition]

pressure of dry gas

P

1

=

T

2

P

2

V

2

×

V

1

T

1

=

−245

1×0.085

×

0.1

273

=0.94714

Aqueous tension=P

observed

−P

drygas

=0.92−0.94714 atm= −0.0271