A certain quantity of gas occupies a volume of 0.8L collected over water at 300 K and a pressure 0.92 bar K. The same gas occupies a volume of 0 08 L at STP in dry conditions. Calculate the aqueous tension at 300
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Pdry gas = Pobserved − aqueous tensionAqueous tension = Pobserved − Pdry gasPobserved = 0.9Pdry gas = ?According to combined gas law P1V1T1 = P2V2T2[Experimental condition STP condition]Pressure of dry gas P1 = P2V2T2 × T1V1 = 1× 0.080283 × 2730.1 = 0.7717 atmAqueous tension = Pobserved − Pdry gas = 0.9 − 0.7717 atm = 0.1283 atm
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