A certain resistance thermometer is found to have a resistance R of 90.35ohms when its bulb is placed in water at the triple point temperature (273.16k). What teùperature in degree celcius and degree fahrenheint is indicated by the thermometer if the bulb is placed in an environment such that it's resistance is 96.28ohms.
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Answer:
temperature is 64.4°F,18celcius
Explanation:
temp(t)=X/Xtrip×273.16K
where x is the thermometric property of material
equal to the resistance of thermometer.
=96.28/90.35×273.16K
=291.09K
temperature of bulb is 291.09K
hence in celcius
From
- t(K)=273.16K+T(CELSIUS)
- 291.09K=273.16K+T(CELSIUS)
- T(CELSIUS)=291.09K-273.16K
- T(CELSIUS)=18CELSIUS.
temperature in farenheit
Formula
(18°C × 9/5) + 32 = 64.4°F
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