Question

A certain sample of calcium carbonate contains 4.86 moles. What is the mass in grams of this sample

Answer 1

Answer:

Mass of CaCO₃ in the sample = 486 g

Explanation:

Molecular mass of CaCO₃    M = 40 + 12 + 3x 16

                                                   = 40 +12 + 48

                                                   = 100 g

Mass of sample m = n M

                               = 4.86 x 100

                                = 486 g