A certain small computer has a 4k ram and a 12k rom. The number of locations in memory are available both for introducing and rrertriving data
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You need log2(n) bits to address n bytes. For example, you can store 256 different values in an 8 bit number, so 8 bits can address 256 bytes. 210 = 1024, so you need 10 bits to address every byte in a kilobyte.
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