Question

A certain soring hangs vertically. When a body of mass M = 1.65 Kg is suspending from

it. Its length increase by 7.33 cm. The spring is then mounted horizontally and a block of mass m

= 2.43 Kg is attached to the spring. The block is free to slide a frictionless horizontal surface find

(a) What is the force constant K of spring???

(b) How much horizontal force is required to stretch the spring of distance 11.6 cm????

(c) If a spring covered a distance of 11.6 cm what will be its period??/​

Answer 1

Answer:

1×g=Kx

3g=K(x+5)

3

1

=

x+5

x

x=2.5

10=K×2.5×10

2

K=400Nhm

ω=

m

K

ω=

3

400

V

max

=Aω

=10×15

2

3

400

=1.154m/sec