Question

A certain sound wave in air has a speed 340m/s and wavelength 1.7m for this wave calculate
a) the frequency b) the period

Answer 1

Answer:a) 200Hz, b) 0.005s.

Explanation:a) v=n× lambda, where v= velocity of sound wave, n= frequency, lambda= wavelength.

So, velocity= frequency×wavelength

=> Frequency= velocity/ wavelength

= 340/1.7=200Hz.

So, frequency= 200Hz.

b) Time period or Period= 1/ frequency

=1/200=0.005s.

So, Period or time period is 0.005s.

Hope this helps.

Answer 2

Frequency, f = 200 Hz

Time period, T = 5 ms

Explanation:

Given that,

Speed of sound wave, v = 340 m/s

Wavelength of the sound wave, $\lambda=1.7\ m$

(a) Frequency of wave is given by the relation as follows :

$v=f\lambda$

$f=\dfrac{v}{\lambda}$

$f=\dfrac{340\ m/s}{1.7\ m}$

f = 200 Hz

(b) The reciprocal of frequency is called time period of the wave. It is given by :

$T=\dfrac{1}{f}$

$T=\dfrac{1}{200\ Hz}$

$T=0.005\ s$

or

T = 5 ms

Hence, this is the required solution.

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