Question

a certain sum amount to rupee 24080 in 9 month at 6% compounded quarterly determine the sum​

Answer 1

Given : A certain sum amount to rupee 24080 in 9 month at 6% compounded quarterly.

　

To find : Determine the sum.

　

☯ Solution : We can use “Compounded interest” formula to solve this question.

　

Formula : Amount = Principal (1 + Rate)^n.

　

$:\implies\sf{Rate = \dfrac{6}{4 \times 100}}$

　

$:\implies\sf{Rate = \dfrac{6}{400}}$

　

$:\implies{\sf{\underline{\boxed{\sf{Rate = 0.015}}}}}$

　

　

$:\implies\sf{Time = \dfrac{9}{12 \times 4}}$

　

$:\implies\sf{Time = \dfrac{9}{48}}$

　

$:\implies{\sf{\underline{\boxed{\sf{Time = 0.1875}}}}}$

　

Applying formula :

$:\implies\sf{24080 = Principal \: (1 + 0.015)^{0.1875}}$

　

$:\implies\sf{24080 = Principal \times 1.00279}$

　

$:\implies\sf{Principal = \dfrac{24080}{1.00279}}$

　

$:\implies{\underline{\boxed{\sf{Principal = 24013.003}}}}$

　

Therefore, 24013.003 is the required answer.

Answer 2

Answer:

Here, Amount = Rs. 24080.00

Time = 9 months = 3/4 yr

rate of interest = 6%

P = ?

We know,

A = P ( 1 + r / 400 )4n

=> 24080 = P ( 1 + 6/400)4x3/4

=> 24080 = P(406/400)3

=> 24080 = P (1.015)3

=> 24080 = P x 1.0456

=> P = 24080/1.0456

=> P = 23029.84 (appprox)