A certain sum amounts rs 4500 in 2 years and 6750 in 4 years by compound interest find the sum?
( 1 ) 4000
(2) 2500
(3) 3000
(4) 3050
Answers
Answered by
1
Given Amount = 4500, n = 2 years.
We know that A = P(1 + r/100)^n
4500 = P(1 + r/100)^2 ------ (1)
Given Amount = 6750, n = 4 years.
We know that A = P(1 + r/100)^n
6750 = P(1 + r/100)^4 ------ (2)
On solving (1) & (2), we get
6750/4500 = (1 + r/100)^4/(1 + r/100)^2
3/2 = (1 + r/100)^2 ------- (3)
Substitute (3) in (1), we get
4500 = P * 3/2
9000 = 3P
P = 3000.
Therefore the sum = 3000.
Hope this helps!
We know that A = P(1 + r/100)^n
4500 = P(1 + r/100)^2 ------ (1)
Given Amount = 6750, n = 4 years.
We know that A = P(1 + r/100)^n
6750 = P(1 + r/100)^4 ------ (2)
On solving (1) & (2), we get
6750/4500 = (1 + r/100)^4/(1 + r/100)^2
3/2 = (1 + r/100)^2 ------- (3)
Substitute (3) in (1), we get
4500 = P * 3/2
9000 = 3P
P = 3000.
Therefore the sum = 3000.
Hope this helps!
siddhartharao77:
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Answered by
1
Hi,
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