Question

a certain sum amounts to rupees 2970.25 in two years at 9% p. a. compounded annually. find the sum

Answer 1

Principal (P) = ?
Rate of interest (R) = 9% per annum
Time (n) = 2 years
Amount (A) = Rs. 2970.25

We know that,
$= > A = P {(1 + \frac{r}{100} )}^{n} \\ \\ = > 2970.25 = P {(1 + \frac{9}{100}) }^{2} \\ \\ = > \frac{297025}{100} = P {( \frac{100 + 9}{100} )}^{2} \\ \\ = > \frac{297025}{100} = P {( \frac{109}{100}) }^{2} \\ \\ = > \frac{297025}{100} = P \times \frac{11881}{10000} \\ \\ = > \frac{297025}{100} \times \frac{10000}{11881} = P \\ \\ = > 2500 = P$

Hence, the Principal (P) [the sum] is Rs. 2500

Answer 2

HEY MATE HERE IS YOUR ANSWER

Principal {P} =?
Time {T} = 2 years
Rate {R} = 9% p. a
Amount {A} = 2970.25 ₹
_________
| Solution :- |
~~~~~~~~~~

We know,

$= > \: a = {p(1 + \frac{r}{100} )}^{t} \\ = > \: 2970.25 = {p(1 + \frac{9}{100}) }^{2} \\ \\ = > \: \frac{297025}{100} = p(1 + \frac{81}{10000}) \\ \\ = > \: \frac{297025}{100} = p( \frac{11881}{10000} ) \\ \\ = > p = \frac{297025}{100} \times \frac{10000}{11881} \\ \\ p= > \: 2500$
Therefore Principal is ₹ 2500