a certain sum invested at compound interest become rupees 34560 in 8 years and rupees 24000 in 6 years. what is the amount after 5 years.
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amount=p(1+R/100)^y
34560=24000(1+R/100)^2
144/100=(1+R/100)^2
1+R/100=12/10
R/100=2/10
R=20
24000=p(1+R/100)(1+R/100)^5
24000×5/6=p(1+R/100)^5
20000=amount
34560=24000(1+R/100)^2
144/100=(1+R/100)^2
1+R/100=12/10
R/100=2/10
R=20
24000=p(1+R/100)(1+R/100)^5
24000×5/6=p(1+R/100)^5
20000=amount
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