Math, asked by hgsrky3552, 1 year ago

A certain sum invested at compound interest becomes rs.6,500 after a period of 6 years and rs.7,800 after a further period of 2 more years. The amount due after a further period of 2 more years is

Answers

Answered by manetho
8

Answer:

Rs.9360

Step-by-step explanation:

WE KNOW THAT amount in compound interest is given by

A= P(1+i)^n

P(1 + i)^6 = 6500

P(1 + i)^8 = 7800

dividing

(1 + i)^2 = 78/65 = 6/5

P (1 + i)^10 = P(1 + i)^8 * (1 + i)^2 = 7800 × 1.2 = 9360

Answered by rani76418910
4

Amount after 10 years = 9360

Explanation:  

Given that, Amount after 6 years  = 6500

Amount after 8 years  = 7800

As we know that,

Amount = Sum + Interest  = P + I

Amount = Sum + Interest   = P + \frac{P \times R \time T}{100}

Amount = P(1 + \frac{R}{100})^{T}           ( by Binomial theorem)

A_{1} = 6500 = (1 + \frac{R}{100})^{6} ……(1)

A_{2} = 7800 = (1 + \frac{R}{100})^{8} ……(2)

On dividing equation (2) by (1) we get,

 (1 + \frac{R}{100})^{2} = \frac{6}{5}  

(1 + \frac{R}{100})^{10} = (1 + \frac{R}{100})^{8}\times(1 + \frac{R}{100})^{2}

Amount after 10 years  = 7800 \times \frac{6}{5} = 9360

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