A certain sum is divided among a,b and
c. in such a way that a gets rs 40 more than the half of the sum.b gets rs 120 less than 3/8 of the sum and c gets 200 what is the total sum
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a=40+1/2(sum)
b=3/8(sum)-120
c=200
a+b+c=sum
40+1/2(sum)+3/8(sum)-120+200=sum
120=sum- 1/2sum-3/8sum
120=(8sum-4sum-3sum)/8
120=sum/8
so sum=120×8=rs.960
please mark it as a brainliest answer
b=3/8(sum)-120
c=200
a+b+c=sum
40+1/2(sum)+3/8(sum)-120+200=sum
120=sum- 1/2sum-3/8sum
120=(8sum-4sum-3sum)/8
120=sum/8
so sum=120×8=rs.960
please mark it as a brainliest answer
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