A certain sum is divided among A, B and C in such a way that A gets 3 times as much as B, B receives 2 times as much as C. If A receives rs.1500 more than C, what was the sum that divided?
Answers
A/B = 3/1. B/C = 2/1. A= 1500+ C
1500+C / B = 3/1 --- B= 1500+C/3 substituting B value in B/C= 2/1
1500+C/3C = 2/1---
1500+C×1= 2×3C
1500= 5C
C= 300 substituting C value in A= 1500+ C
therefore A= 1800
from B/C = 2/1
B/300= 2/1 -- B= 600
therefore A = 1800 , B = 300 , C = 600
sum of all three is 2700.( you can cross check the values of A,B,C by putting them in given ratio :) )
thank you. hope it helps
The sum that is divided is 13473Rs.
Given:
A sum is divided among A, B and C in such a way that A gets 3 times as much as B, B receives 2 times as much as C and A receives rs.1500 more than C.
To Find:
The sum that is divided.
Solution:
To find the sum that is divided we will follow the following steps:
According to the question.
Let the C receive = x
A receives rs.1500 more than C,
So,
A = 1500+x
Now,
B receives 2 times as much as C.
B = 2x
A gets 3 times as much as B,
A = 3 × 2x
Now,
Equating the amount A receives we get,
1500 + x = 3 + 2x
1500 - 3 = 2x - x
1497 = x
A received = 3 × 2x = 3×2×1497 = 8982Rs.
B receives = 2x = 2× 1497 = 2994Rs.
C receives x = 1497Rs.
Total Rs. divided = 8982 + 2994 + 1497 = 13473Rs.
Henceforth, the sum that is divided is 13473Rs.
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