A certain sum is divided among P, Q ,R in such way that P gets rs 95 more than 1/6 th of the sum ,Q gets rs 240 less than 5/8 th of the sum and R gets rs 645 ,what is the total sum involved
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The total sum involved is Rs. 2400
Given -
- P get Rs. 95 more than 1/6th of the sum
- Q get Rs. 240 less than 5/8th of the sum
- R gets Rs. 645
Let the initial amount be x
So ,
P = x/6 + 95
Q = 5x/8 - 240
Now R' share is,
= x - x/6 -95 - 5x/8 + 240
= 5x/24 + 145
According to the question
5x/24 + 145 = 645
By solving the above equation we get
x = 2400
Hence the total sum involved is Rs. 2400
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