Question

A certain sum is divided among P, Q ,R in such way that P gets rs 95 more than 1/6 th of the sum ,Q gets rs 240 less than 5/8 th of the sum and R gets rs 645 ,what is the total sum involved​

Answer 1

Step-by-step explanation:

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Answer 2

The total sum involved is Rs. 2400

Given -

• P get Rs. 95 more than 1/6th of the sum
• Q get Rs. 240 less than 5/8th of the sum
• R gets Rs. 645

Let the initial amount be x

So ,

P = x/6 + 95

Q = 5x/8 - 240

Now R' share is,

= x - x/6 -95 - 5x/8 + 240

= 5x/24 + 145

According to the question

5x/24 + 145 = 645

By solving the above equation we get

x = 2400

Hence the total sum involved is Rs. 2400