A certain sum of money amounts to Rs. 2200 at 5% interest, Rs. 2320 at 8% interest in the same period of time. The period of time is:.
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Answered by
1
The simple interest formula is
SI = PRT/100
And the amount after time T is given by
Amt = P + SI = P + PRT/100
Amt = P (1 + RT/100)
So, our amount for 5% rate is
2200 = P [ 1 + (5)(T)/100 ]
2200 = P [ 1 + 5T/100 ]
And our amount for 8% rate is
2320 = P [ 1 + (8)(T)/100 ]
2320 = P [ 1 + 8T/100 ]
So, dividing these 2 we get
2200÷2320 = P [ 1 + 5T/100 ] ÷ P [ 1 + 8T/100 ]
55 ÷ 58 = [ 1 + 5T/100 ] ÷ [ 1 + 8T/100 ]
55 ÷ 58 = [ 100 + 5T ] ÷ [ 100 + 8T ]
Cross multiplying, we get
55(100 + 8T) = 58(100 + 5T)
5500 + 440T = 5800 + 290T
150T = 300
T = 2
Therefore, time period is 2 years.
SI = PRT/100
And the amount after time T is given by
Amt = P + SI = P + PRT/100
Amt = P (1 + RT/100)
So, our amount for 5% rate is
2200 = P [ 1 + (5)(T)/100 ]
2200 = P [ 1 + 5T/100 ]
And our amount for 8% rate is
2320 = P [ 1 + (8)(T)/100 ]
2320 = P [ 1 + 8T/100 ]
So, dividing these 2 we get
2200÷2320 = P [ 1 + 5T/100 ] ÷ P [ 1 + 8T/100 ]
55 ÷ 58 = [ 1 + 5T/100 ] ÷ [ 1 + 8T/100 ]
55 ÷ 58 = [ 100 + 5T ] ÷ [ 100 + 8T ]
Cross multiplying, we get
55(100 + 8T) = 58(100 + 5T)
5500 + 440T = 5800 + 290T
150T = 300
T = 2
Therefore, time period is 2 years.
Answered by
0
Answer:
different rate =8-5=3%
3%=120
5%=120/3×5
=200
P=2200-200
=2000
T=Si×100/P×R
200×100/2000×5
=2Years ans
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