Question

A certain sum of money becomes three times of itself in 20 years at si in how many years does it become double of itself at the same rate of essay

Answer 1

A certain sum of money becomes three times of itself in 20 years at certain rate of
simple interest .

Using simple interest formula we get

A=PRT

Where

A=Amount
P=Principal
R=Rate
T=Time

ATQ

3A=A ×R ×20 ... (1)

2A=A ×R ×T ... (2)

Multiplying equation 1 by 2 and equation 2 by 3

6A=40AR

6A=3ART

40AR=3ART

T = 40/3

T= 13.3 years

Answer 2

Answer:

40/3 years = 13.3 years

Step-by-step explanation:

Given Problem:

A certain sum of money becomes three times of itself in 20 years at si in how many years does it become double of itself at the same rate of essay.

Solution:

We know that,

Simple Interest Formula:

$\huge\boxed{\bigstar A = PRT\bigstar}$

Where,

A = Amount

P = Principal

R = Rate

T = Time

Let the Principal amount be x,

$\sf =>3x = x \times R \times20 - - - - Equation 1\\\\\ =>2x = x\times R \times T - - - - -Equation 2\\\\\ Multiply\; equation\; 1\; by\; 2\; and\; equation\; 2\; by\; 3\; and\; subtract\;Eq\; 2\;from\; Eq\; 1\\\\\ We\;will\;get,\\\\\ 40 R - 3RT = 0\\\\\bigstar Hence,\\\ T = 40/3 years = 13.3 years.\bigstar$