Math, asked by Frenyl, 5 months ago


A certain sum of money doubles itself in 6
years. In how many years will it be three
times at the same rate of simple interest?​

Answers

Answered by godessofmoon2007
4

Answer:

So, P + P * r *6/100 = 2P

Or, p*r*6/100 = 2P - P = P

Or, r = 100/6 = 16.67 %

For sum to be treble, the interest should be twice the Principle I.e. P * (16.67/1t00) * t = 2P where t is the period when the sum will be 3 times.

Or, t = 100 * 2/16.67 = 12 years. Ans.

Simply you can also give a statement that when sum is doubled in 6 years for simple interest, the sum will be tripled in 6 * 2 = 12 years

Answered by Anonymous
5

Answer:

Let the sum of money that's principal be x.

Time = 6years

Amount after 6 years becomes double = 2x

Therefor, Simple Interest = Amount - Principal = 2x-x = x

Rate per annum = SI×100/ P×T = x×100/x×6 = 100/6 = 50/3 = 16.66 % approx

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